Ὁ Πενταμετρικὸς Κύκλος – The Pentametric Cycle
✦ Exploratory · beyond the papers, not peer reviewed observation, not a theorem

A curiosity: the ratio √10 / 3

In the construction, a right triangle with legs 1 and 1/3 keeps appearing; it carries Holden's angle arctan(1/3). Its hypotenuse is √10/3 ≈ 1.05409. As a frequency ratio this is very close to a semitone. This page lets you measure and hear how close, without claiming more than the numbers show.

The numbers

hypotenuse
√(1 + 1/9) = √10/3 = 1.0540925534
its square
10/9 exactly
size in cents
600 · log₂(10/9) = 91.20
angle at E
arctan(1/3) ≈ 18.43°

A cent is 1/100 of an equal-tempered semitone; most listeners notice differences of about 5 cents or more between two steady tones.

Compared with the semitones of music

intervalratiocentsdifference from √10/3listen

Two facts stand out. The square of √10/3 is exactly 10:9, the just “minor whole tone” of Ptolemy's syntonic diatonic, so √10/3 is exactly half of that tone. And it lies within about 1 cent of the Pythagorean semitone, the limma 256:243, whereas the equal-tempered semitone is almost 9 cents away.

Half a schisma: the exact link to the limma

The “about 1 cent” between √10/3 and the limma has an exact name. Square both sides:

(√10/3)² = 10/9 = (256/243)² × 32805/32768

(check: 65536 × 32805 / (59049 × 32768) = 65610/59049 = 10/9). The last factor, 32805/32768 = 1.954 cents, is the schisma of tuning theory. So √10/3 is the limma widened by exactly half a schisma, 0.977 cents: the minor whole tone 10:9 is two limmas and one schisma.

√10/3 − limma
0.97686 cents = ½ schisma, exactly
24 × that gap
23.44465 cents = 12 schismas
Pythagorean comma
531441/524288 = 23.46001 cents
difference
0.01536 cents (the “atom of Kirnberger”)
3:2 less one schisma
16384/10935 = 700.00128 cents (Kirnberger's fifth)
12 such fifths − 7 octaves
0.01536 cents

Twelve pure fifths 3:2 overshoot seven octaves by the Pythagorean comma, which is why a circle of pure fifths never closes. Twenty-four of these half-schismas (twelve schismas) come within 0.015 cents of that comma, so narrowing each pure fifth by one schisma, that is by (√10/3 ÷ limma)², gives a fifth of 700.0013 cents: equal temperament's fifth to a thousandth of a cent, and a circle that misses closing by only 0.015 cents. You can hear it on The chord wheel (Pentametric circle of fifths, fifth: Kirnberger).

exact the identity is plain arithmetic. known the schisma, the near-equality of twelve schismas and the comma, and the fifth 16384/10935 are classical tuning theory (J. P. Kirnberger, 18th century, proposed this fifth as a whole-number stand-in for equal temperament). What is new here is only the route: from the triangle with legs 1 and 1/3 to that fifth. No fraction of whole numbers can close the circle exactly, since 27/12 is irrational; and √10 only brings square roots, never a 12th root of 2.

Can it replace the equal-tempered semitone?

An equal temperament must close at the octave: twelve equal steps have to make exactly 2:1. Twelve steps of 21/12 give 1200 cents. Twelve steps of √10/3 give only 1094.4 cents, about a semitone short of the octave; it would take 13.16 of them to reach 2:1. So √10/3 cannot be the step of a scale that repeats at the octave. It could be the step of a non-octave scale, a family that composers have explored (for example Wendy Carlos's alpha and beta scales, or the Bohlen–Pierce scale), and that is a legitimate artistic direction rather than a correction of equal temperament.

Status: the closeness of √10/3 to 21/12 is a numerical observation; its distance from the limma is exactly half a schisma (shown above), which ties it to known tuning theory. Observation by the author in GeoGebra, where the triangle has EF = 1, FB3 = 1/3 and EB3 = 1.0540925533894…